Arithmetic Ability
 Probability

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Q.

Three unbiased coins are tossed. What is the probability of getting at most two heads?

View Answer

Correct choice: B

Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH} Let E = event of getting at most two heads. Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}. P(E) =n(E)/n(S)=7/8.
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